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How to become a medical and dental technician

Official title: Medical and dental technicians

Also called: Technician, Dental fitter, Ecg technician, Eeg technician, Dental ceramist, Dental engineer, Dental mechanic, Medical engineer, Dental hygienist, Dental technician, Trauma technician, Cardiac technician

Medical and dental technicians operate, calibrate and maintain cardiographic and encephalographic testing equipment, assist in the conduct of post mortems, give simple dental treatments, fit artificial limbs and hearing aids, and undertake a wide range of related medical and dental tasks.

Main tasks

How to become one

Entrants usually possess GCSEs/S grades, BTEC/SQA awards, an Intermediate GNVQ/GSVQ level II or A levels/H grades. Training may last up to five years depending upon the field and method of study. Professional qualifications and NVQs/SVQs at level 3 are available in some areas.

Ways in

Pay · Outlook

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Questions people ask

How do I become a medical and dental technician?

Entrants usually possess GCSEs/S grades, BTEC/SQA awards, an Intermediate GNVQ/GSVQ level II or A levels/H grades. Training may last up to five years depending upon the field and method of study. Professional qualifications and NVQs/SVQs at level 3 are available in some areas.

How much does a medical and dental technician earn in the UK?

Median full-time pay is £29,931 a year (Office for National Statistics). The middle half earn £26,955 to £36,120.

Is a medical and dental technician a growing career in the UK?

Yes. Employment is projected to grow 10% by 2035, from about 33,300 to about 36,600 people (Department for Education).

Do you need a degree to become a medical and dental technician?

Not always. 52% of people in this job hold a bachelor's degree or higher. Ways in include: Medicine & Dentistry degrees; Nursing & Midwifery degrees; Hearing aid dispenser (level 5).

Sources

Updated 2026-10-03

Graduate outcomes: Discover Uni dataset, HESA (www.hesa.ac.uk), licensed under CC BY 4.0 (creativecommons.org/licenses/by/4.0). Aggregated by subject and adapted by Peernovo.